I found the structure of glycerol trioleate here:
http://newsearchch.chemexper.com/cheminf鈥?/a>
It has three double bounds and three C=O groups. You would need 3*2 + 3 = 9 hydrogen atoms = 4.5 H2 molecules to reduce these.
Therefore you need 4.5 mol to reduce 1 mol of glycerol trioleate.
The stuff has a molecular mass of 885.44916 gram (same page), so we have 1/885.44916 mol of it. Therefore we need 4.5/885.44916 mol of H2. At STP this is 22.4*4.5/885.44916 liter.
After some button punching I get 114 ml.
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